How to do a function pointer to "malloc" and "free"?
rempas
rempas at tutanota.com
Sun Oct 10 10:44:15 UTC 2021
I'm having the following C code:
```
static void* (*ppmalloc)(size_t) = malloc;
static void (*ppfree)(void*) = free;
```
I want to covert this code in D so I try to do the following:
```
static void* function(size_t)*ppmalloc = malloc;
static void function(void*)*ppfree = free;
```
If I do that, I'm getting the following error message:
```
Error: function `core.stdc.stdlib.malloc(ulong size)` is not
callable using argument types `()`
```
I'm also trying to do the same using "pureMalloc" and "pureFree"
instead but this time I'm getting the following error:
```
cannot implicitly convert expression `pureMalloc()(size_t size)`
of type `void` to `extern (C) void* function(ulong)*`
```
Any ideas?
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