Function template as template parameter
Salih Dincer
salihdb at hotmail.com
Sun Dec 11 13:54:34 UTC 2022
On Sunday, 11 December 2022 at 09:43:34 UTC, Andrey Zherikov
wrote:
> Note that callback parameter must be compile-time parameter as
> it represents a member of a type during introspection done by
> `foo`.
I can't quite understand the question, this already works:
```d
void foo(alias callback)()
{
import std.stdio : writefln;
callback.writefln!"%s";
}
void main()
{
auto i = [ 1, 2, 3 ];
auto s = ["foo", "bar", "zoo"];
foo!i;
foo!s;
foo!"hello, world!";
enum a = 11, b = 22;
foo!(a + b);
} /*
[1, 2, 3]
["foo", "bar", "zoo"]
hello, world!
33
*/
```
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