unordered output of an associated array of associated arrays

[H. S. Teoh]

On Tue, Jan 25, 2022 at 02:04:26AM +0000, forkit via Digitalmars-d-learn wrote:
[...]
> // --
> module test;
> 
> import std;
> 
> void main()
> {
>     auto aaTable =
>       ([
>        "typeB" : [ 100000002 : [1, 1, 0, 0, 0, 0, 0, 0],
>                    100000001 : [1, 0, 0, 0, 0, 0, 0, 0]
>                  ],
>        "typeC" : [ 100000007 : [1, 1, 1, 1, 1, 1, 0, 0],
>                    100000006 : [1, 1, 1, 1, 1, 1, 0, 0]
>                  ],
>        "typeA" : [ 100000005 : [1, 1, 1, 1, 1, 0, 0, 0],
>                    100000003 : [1, 1, 1, 0, 0, 0, 0, 0],
>                    100000004 : [1, 1, 1, 1, 0, 0, 0, 0]
>                  ]
>       ]);
> 
>     string[] orderedKeyPairSet;
> 
>     foreach (key, pair; aaTable.byPair)
>     {
>         foreach(k, p; pair.byPair)
>             orderedKeyPairSet ~= key ~ ":" ~ k.to!string ~ ":" ~
> p.to!string;
>     }
> 
>     orderedKeyPairSet.sort;
> 
>     foreach(s; orderedKeyPairSet)
>         writeln(s);

That's the *easy* way out??  Try this instead:

	aaTable.keys.sort.each!((k) {
		aaTable[k].keys.sort.each!((kk) {
			writefln("%s:%s:%s", k, kk, aaTable[k][kk]);
		});
	});


T

-- 
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