Thinking about the difference between fixed and 'dynamic' arrays.

[matheus]

On Tuesday, 29 November 2022 at 23:25:46 UTC, DLearner wrote:
> On Tuesday, 29 November 2022 at 19:06:20 UTC, rikki cattermole 
> wrote:
> [...]
>
> Please see the following example:
> ...

I think this was discussed before a few weeks ago here (But I 
don't remember the thread), and this is a design choice, for 
example this:

     VarArr2 = VarArr1;

VarArr2 is just pointing to the same address of VarArr1 as you 
can see by:

    writeln(VarArr1.ptr);
    writeln(VarArr2.ptr);

To do what you want, you need to use "dup":

    VarArr2 = VarArr1.dup;

Now it will work as you expect.

I think this is confusing but in the end it's a design choice, 
instead of copy just point, and if you need to copy, you need to 
it explicitly.

Matheus.