Negating a short?

[Matheus]

On Wednesday, 6 November 2024 at 00:00:48 UTC, Dennis wrote:
> On Tuesday, 5 November 2024 at 20:29:08 UTC, Andy Valencia ...
> You can also use an assignment operator, which allows overflow 
> without explicit cast:
>
> ```D
> s *= -1;
> ```
> ...

Hi Dennis,

Shouldn't these two act the same?

void main(){
     short i = 1;
     i *= -1;  // Works
     i = i*-1; // Gives: Error: cannot implicitly convert 
expression `cast(int)i * -1` of type `int` to `short`
}

Matheus.