When not capturing the return value of a string mixin expression, I get "found `End of File` when expecting `;`"

[realhet]

On Friday, 12 September 2025 at 12:23:21 UTC, Nick Treleaven 
wrote:
> On Friday, 12 September 2025 at 09:17:10 UTC, realhet wrote:
>> On Friday, 12 September 2025 at 08:44:47 UTC, Stefan Koch 
>> wrote:
>>> On Friday, 12 September 2025 at 08:36:42 UTC, realhet wrote:

I did a complete 'martix' of these combinations and accidentally 
found the way how I did it already in the past.  Actually my 
things were changed, it's not related to the DMD/LDC version, 
sorry for the false suspection.

So the solution is to put the mixin(expr) into a () and then the 
expression it will act BOTH an expression with a return value and 
a statement with unused return value.

import std;

```d
void main() {
   enum expr = `(){return 4;}()`; //expression

   (){return 4;}()       ;   //<- works
   auto x = mixin(expr)  ;   //<- works
   auto y = (mixin(expr));   //<- works
//mixin(expr)           ;   //<- fails. mixin expects statement
   (mixin(expr))         ;   //<- THIS IS THE WHEY! :D
}
```
note: The expressio must be a lambda, othewise the compiler will 
detect no side effects and refuse to use it as a statement.

(x);  <- Is not a construct that comes to my mind as useful, but 
this was it. This forces the mixin to expect an expression and 
not a statement.

Thank You all to for the help!