Bizarre way to 'new' arrays

[BCS]

Frits van Bommel wrote:
> BCS wrote:
 >>
[...]
 >>
> 
> 
> Now try replacing this one:
> 
> int* bytes = new int(1024*1024);    // 1 MB
> 
> Doesn't scale all that well, does it? :P

If you want an int[2^20] this wont do it. But if you want a dynamically 
created int that holds that value, that can be done.
For a huge array, I'd ship it mapped into a data file, or something like 
that.

The array in the first case is there for if you have more than one value.
e.i.:   const static int[] store = [-3,5,7,26,1024,1022];

<code>
import std.stdio;
void main()
{        // works for more than one value
      const static int[] store = [1024*1024];

          // get a value
      int* i = store[0..1].dup.ptr;
      writef(*i,\n);

          // change it
      *i = 4;
      writef(*i,\n);

          // original is unchanged
      i = store[0..1].dup.ptr;
      writef(*i,\n);

      int j;
      j= 1024*1024;

		// non const values anyone??
      i = (&j)[0..1].dup.ptr;

           // change it (again)
      *i = 4;
      writef(*i,\n);

          // original is unchanged
      writef(j,\n);
}
</code>