stdio line-streaming revisited
kris
foo at bar.com
Thu Mar 29 12:13:02 PDT 2007
Andrei Alexandrescu (See Website For Email) wrote:
> kris wrote:
>
>> Andrei Alexandrescu (See Website For Email) wrote:
>>
>>> kris wrote:
>>>
>>>> Sean Kelly wrote:
>>>> [snip]
>>>>
>>>>> I must be missing something. Why is the following not acceptable?
>>>>>
>>>>> import tango.io.Console;
>>>>>
>>>>> void main()
>>>>> {
>>>>> char[] name;
>>>>> Cout( "Please enter your name: " ).flush;
>>>>> Cin.nextLine( name );
>>>>> Cout( "Hello, " )( name )( "!" );
>>>>> }
>>>>
>>>>
>>>>
>>>>
>>>> There used to be a tango/example like this variation:
>>>>
>>>> import tango.io.Console;
>>>>
>>>> void main()
>>>> {
>>>> Cout ("Please enter your name: ").flush;
>>>> Cout ("Hello, ") (Cin.get);
>>>> }
>>>
>>>
>>>
>>> Ah, also, the last line is translated into:
>>>
>>> Cout.opCall("Hello, ").opCall(Cin.get);
>>>
>>> D does not specify evaluation order, so the code might end up
>>> printing "Hello, " before reading the standard input. It's funny this
>>> does not happen exactly because of buffering, but the program has no
>>> control over the buffering so it should assume flushing could happen
>>> at any time. So the correct code is:
>>>
>>> auto name = Cin.get;
>>> Cout("Hello, ")(name);
>>
>>
>> Well aware of that, thanks. BTW: evaluation order has been clarified
>> before, on a similar topic.
>
>
> Is that clarification identical with the one posted by Frits?
>
> Andreo
Walter clarified, a long time ago, that D would evaluate chained-calls
from left to right. I suggest you ask Walter?
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