Invariant Question (yes, another one)

[Regan Heath]

Janice Caron wrote:
> On 11/15/07, Steven Schveighoffer <schveiguy at yahoo.com> wrote:
>> Your first data type is an AA with invariant strings as keys and values.
>> HOWEVER, the AA itself is not invariant.  Suppose after you converted to an
>> AA with const strings as keys and values, you replaced one of the values
>> with a mutable string cast into a const string.
> 
> Yes, you're right.
> 
> invariant(char)[][] won't implicitly convert to const(char)[][]
> either, for the same reason.
> But...
> invariant(char[])[] will implicitly conver to const(char[])[]
> 
> But here's the odd thing...
> 
> invariant(char[])[] will implicitly conver to const(char[])[]
> but
> invariant(char[])[int] won't implicitly convert to const(char[])[int]
> 
> The only difference is the int in the square brackets.

void main()
{
	char[] fred = "fred".dup;

	invariant(char)[][int] iaa;
	const(char)[][int] caa;

	iaa[1] = "world";
	caa = iaa;  //pretend this is allowed

	caa[2] = fred;
}

Using the same reasoning :)

Regan