Strange performance behavior
Bill Baxter
dnewsgroup at billbaxter.com
Wed Sep 19 18:28:53 PDT 2007
Bruce Adams wrote:
> Bill Baxter Wrote:
>
>> Bill Baxter wrote:
>>> Marius Muja wrote:
>>>> I have noticed the following strange (at least for me) performance
>>>> behavior with one of my programs. It is a program that does some
>>>> scientific computations and while trying to optimize it I noticed that
>>>> the code from case_B below executes faster (almost twice as fast) as
>>>> the code in case_A. This is a bit counterintuitive for me, since in
>>>> case _B there is also the cost of the function call (or should be the
>>>> same if the function is inlined).
>>>> Can anybody shed some light on why it's behaving this way?
>>>>
>>>> case_A:
>>>> -------------------------------
>>>> foreach (i,index; indices) {
>>>> foreach (k, inout value; centers[belongs_to[i]])
>>>> value += vecs[index][k];
>>>> }
>>>> ----------------------------------
>>>>
>>>> case_B:
>>>> -------------------------------
>>>> void addTo(T,U)(T[] a, U[] b) {
>>>> foreach(index, inout value; a) {
>>>> value += b[index];
>>>> }
>>>> }
>>>> ....
>>>> foreach (i,index; indices) {
>>>> addTo(centers[belongs_to[i]],vecs[index]);
>>>> }
>>>> _______________________________
>>> My guess would be the compiler's failure to optimize[*] away the [index]
>>> indexing in A. So you do 2 lookups per iteration rather than just one.
>>> If so then this should be just as fast as case_B:
>>>
>>> foreach (i,index; indices) {
>>> auto vecs_i = vecs[index];
>>> foreach (k, inout value; centers[belongs_to[i]])
>>> value += vecs_i[k];
>>> }
>>>
>> Forgot the footnote!:
>>
>> [*] It may not really be a failure of the optimizer -- maybe it's
>> unreasonably difficult to determine absolutely that vecs won't changed
>> by the operation '+= vecs[index][k]'.
>>
>> --bb
>
> <shields up>
> This is exactly the sort of thing where const would help :)
> </shields down>
Uh oh... you should have left the shields up. Now you're unprotected...
--bb
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