const challenge

[Kris]

Sergey Gromov Wrote:

> 
> 'const' and 'in' work exactly the same, just checked.
> 
> void foo(in char[] s) { writeln(s); }
> void bar(const char[] s) { writeln(s); }
> 
> foo("test");
> foo("test"[0..2]);
> foo("test".dup);
> bar("test");
> bar("test"[0..2]);
> bar("test".dup);
> 
> compiles and works correctly.
> 
> SnakE


Thank you, SnakE, for clarifying that. I'd been harbouring a misguided impression that invariant would not implicitly cast to const