array setting with objects (bug?)
Denton Cockburn
diboss at hotmail.com
Tue Mar 4 06:00:18 PST 2008
On Tue, 04 Mar 2008 08:53:35 -0500, Jarrett Billingsley wrote:
> "Denton Cockburn" <diboss at hotmail.com> wrote in message
> news:pan.2008.03.04.13.32.00.785638 at hotmail.com...
>
>> arr[] = new C; /* this is the offending line, it doesn't happen if I */
>
> This creates *one* instance of C and sets all the elements of arr to point
> to that single instance.
>
> Hence:
>
>> [5]
>> [5,5]
>> [5,5,5]
>
> You keep modifying the same array. :)
Yeah, would be nice if that was mentioned somewhere.
in the section of the docs where:
s[] = 3; // same as s[0] = 3, s[1] = 3, s[2] = 3
I (naively) expected:
s[] = new C; // to be same as s[0] = new C, s[1] = new C, s[2] = new C
or
s[] = foo(); // where foo returns an object (a different one each time)
easy to work with and around as is, but would be rather nice to be able to
do what I just stated. Syntactic sugar for 2.0?
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