Can't declare "template parameter which takes value of any type"
Russell Lewis
webmaster at villagersonline.com
Mon Mar 17 08:02:10 PDT 2008
I'd like to propose that we need a syntax for a template parameter which
takes "a value of any type."
Of course, you can currently write templates which take values:
BEGIN CODE
template foo(int I) { ... whatever ... }
END CODE
You can also declare IFTI functions which take parameters of any type:
BEGIN CODE
void bar(TYPE)(TYPE argument) { ... whatever ... }
END CODE
But sometimes, you don't want to run a function...you want to declare a
template which takes a value, but there are multiple types that the
value might have. Consider this snippet from real code I'm trying to write:
BEGIN CODE
void DoThing(char argument, void delegate() callback)
{ ... whatever ... }
void DoThing(string argument, void delegate() callback)
{ ... whatever ... }
... maybe there are lots of DoThing functions ...
... or maybe DoThing is an IFTI function ...
void Chain(alias FUNC, TPL...)(void delegate() callback)
{
FUNC(delegate void()
{
static if(TPL.length > 0)
Chain!(TPL)(callback);
else
callback();
});
}
// here's where the new syntax would be *really* nice
void Chain(char ARG, TPL...)(void delegate() callback)
{
DoThing(ARG,
delegate void()
{
static if(TPL.length > 0)
Chain!(TPL)(callback);
else
callback();
});
}
void main()
{
Chain!('c','h', SomeOtherFunc, 'a','r', VariousFuncs)
(delegate void()
{
writefln("we got a callback!");
});
}
END CODE
In the example above, if DoThing had a lot of overloads, then I would
need to have a specialized Chain template for each type. (If Chain was
part of a library, and DoThing was in some other code, this might be
really difficult.) Worse, if DoThing was an IFTI function, I wouldn't
be able to do this at all.
However, Chain would be trivial to write if we could declare "any sort
of value" parameters:
BEGIN CODE THAT WON'T COMPILE
void Chain(value ARG, TPL...) { ... see above ... }
END CODE
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