foo!(bar) ==> foo{bar}

[bearophile]

Walter Bright:
> The foo.(bar) syntax seems to be sinking.

The Foo{bar} syntax looks nice enough, it's a char long, and I presume q{int} isn't a problem, but from 30 answers seems people don't see problems in the old syntax. So it's not sinking at all.

While in the past I may have listed lots of other things that deserve attention, and some of them seem far more important/urgent.

Bye,
bearophile