Functions with package protection
grauzone
none at example.net
Wed Jun 3 16:06:24 PDT 2009
Robert Fraser wrote:
> grauzone wrote:
>>> Sorry to dig up this old post, but I still don't understand why
>>> 'package' functions cannot be virtual? Is there a good reason for
>>> this? I can't see why we can't use polymorphism on 'package' functions!
>>>
>>> Is there way to make it virtual without making it public? (e.g. a
>>> 'virtual' keyword?)
>>
>> "package" needs to fixes:
>> - package methods must be allowed to be virtual
>> - package methods must be allowed to be accessed from sub packages
>> (module a.b.x should be able to access package identifiers declared in
>> module a.y)
>>
>> I don't understand why these fixes applied, especially because they
>> are completely backward compatible.
>
> "package methods must be allowed to be virtual" isn't
> backwards-compatible. This code will work differently if package methods
> were made virtual:
>
> class A
> {
> package void foo() { printf("A"); }
> }
>
> class B
> {
> package void foo() { printf("B"); }
> }
>
> void main()
> {
> A a = new B();
> a.foo();
> }
I'd say this code relied on a bug, and fixing bugs is always allowed.
Actually, it is very likely that the behavior above wasn't even intended
by the programmer.
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