'final' function implementations in interface definition
HOSOKAWA Kenchi
hskwk at inter7.jp
Sun Jun 7 16:52:05 PDT 2009
Steve Schveighoffer Wrote:
>
> f_twice can be a template:
>
> void f_twice()(int i) { f(i); f(i); }
>
> It's pretty much exactly what you want. It should even work without
> explicit instantiation.
>
> -Steve
I have tried to replace final function in the interface with your code. finally I got following message.
Error: function I.f_twice!().f_twice template member function not allowed in interface I
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