asm code and an inout function argument

[Vladimir A. Reznichenko]

Tim Matthews Wrote:

> On Fri, 15 May 2009 22:29:07 +1200, Robert Fraser  
> <fraserofthenight at gmail.com> wrote:
> 
> > Vladimir A. Reznichenko wrote:
> >> I have a function:
> >>  void test (inout uint a)
> >> {
> >> 	asm
> >> 	{
> >> 		mov a, 0x25;
> >> 	}
> >> }
> >>  The trouble is that the function's call doesn't change the a variable.
> >> Any ideas?
> >
> > Inout variables are pointers.
> 
> 
> Why is it 'inout' and not 'ref' ?

Aren't they the same?