!in operator?

[Stewart Gordon]

Jeremie Pelletier wrote:
> Why is there no !in operator just like there is a !is operator? Is it 
> because this expression evaluates to a pointer to the found element? 
<snip>

Of course not.  This compiles:

void main() {
     char* abc;
     assert (!abc);
}

so why shouldn't !in?

Stewart.