[OT] n-way union
Andrei Alexandrescu
SeeWebsiteForEmail at erdani.org
Tue May 26 06:31:35 PDT 2009
Don wrote:
> Andrei Alexandrescu wrote:
>> I think you can't do better. Complexity is O(n) at a minimum because
>> you need to go through each element. The heap-based algorithm has O(n
>> log m). What you could improve on is the log m factor (m = the number
>> of sets).
>
> Depending on what "going through each element" means. Certainly, if you
> need to move them, you can't beat O(n) moves, but you can definitely get
> O(m*m) < < O(n) comparisons in the best case I described. And that would
> also be the number of splicing operations.
Oh, I see. So yes, comparisons can be reduced. So how exactly do you
think that can be done? By binary searching the upper bound of the head
to find a long run of identical elements?
Andrei
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