Eliminate class allocators and deallocators?
Michel Fortin
michel.fortin at michelf.com
Wed Oct 7 07:56:04 PDT 2009
On 2009-10-06 20:26:48 -0400, Andrei Alexandrescu
<SeeWebsiteForEmail at erdani.org> said:
> The matter has been discussed quite a bit around here and in other
> places. I'm not having as much time as I'd want to explain things. In
> short, destroying without freeing memory avoids dangling references and
> preserves memory safety without impacting on other resources.
>
> It's a safety hack, not a performance hack.
In my opinion, it's mostly an illusion of safety. If you call the
destructor on an object, the object state after the call doesn't
necessarily respects the object invariants and doing anything with it
could result in, well, anything, from returning wrong results to
falling into an infinite loop (basically undefined behaviour). What you
gain is that no object will be allocated on top of the old one, and
thus new objects can't get corrupted. But it's still undefined
behaviour, only with less side effects and more memory consumption.
I don't think it's a so bad idea on the whole, but it'd be more
valuable if accessing an invalidated object could be made an error
instead of undefined behaviour. If this can't be done, then we should
encourage "destructors" to put the object in a clean state and not
leave any dirt behind. But should that still be called a "destructor"?
Perhaps we could change the paradigm a little and replace "deletion"
with "recycling". Recycling an object would call the destructor and
immeditately call the default constructor, so the object is never left
in an invalid state. Objects with no default constructor cannot be
recycled. This way you know memory is always left in a clean state, and
you encourage programmers to safely reuse the memory blocks from
objects they have already allocated when possible.
--
Michel Fortin
michel.fortin at michelf.com
http://michelf.com/
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