alias this and immutable shenanigans
Stanislav Blinov
blinov at loniir.ru
Fri Aug 13 04:22:18 PDT 2010
13.08.2010 9:37, Yao G. wrote:
> Consider this code:
>
> ---
> module test;
>
> struct Foo
> {
> this( int f ) {
> _foo = f;
> }
>
> @property int baz() {
> return _foo;
> }
>
> // alias _foo this;
> // alias baz this;
>
> immutable int _foo;
> }
>
> struct Bar
> {
> this( int f ) {
> _foo = Foo(f);
> }
>
> private:
> immutable Foo _foo;
> }
> ---
>
> If I uncomment the alias _foo this line, I get the following error
> message:
>
> % Test.d(22): Error: can only initialize const member _foo inside
> constructor
>
> WTF! I'm initializing it in a constructor! Is this a bug? Or by design
> you cannot alias this to a immutable member of a struct. It seems that
> there's a hidden temp created that wants to initialize the field.
> Also, I wanted to alias the property Foo.baz, but it also caused the
> following errors:
>
> % Test.d(22): Error: function test.Foo.baz () is not callable using
> argument types (Foo) immutable
> % Test.d(22): Error: expected 0 arguments, not 1 for non-variadic
> function type @property int()
>
> It seems that somehow the property is used as a "setter", not as a
> "getter".
>
> So, my questions are:
> 1. Why is disallowed to alias this an immutable data inside a struct?
> 2. Why is disallowed to alias this a struct "getter" property?
>
>
If you rename Bar._foo to Bar._fooo, you'll see what it complains about
(yep, about A._foo).
When you use 'alias x this', methods not defined for 'typeof(this)' will
be searched in typeof(x). In this case, _foo = Foo( f ) is a constructor
call, but...
If alias is present, _foo = Foo(f) translates to
_foo._foo.opAssign(Foo(f)), or, when you alias to baz, to property
assignment (and you indeed don't have a setter).
Thus being said, I'm not sure if it's a bug or not - seems like an
ambiguity at least.
--
*
*
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