tail const
Michel Fortin
michel.fortin at michelf.com
Wed Dec 1 11:07:09 PST 2010
On 2010-12-01 09:37:08 -0500, Michel Fortin <michel.fortin at michelf.com> said:
> On 2010-12-01 06:17:24 -0500, Jonathan M Davis <jmdavisProg at gmx.com> said:
>
>>> I proposed the following a while ago. First allow the class reference
>>>
>>> to (optionally) be made explicit:
>>> C a; // mutable reference to mutable class
>>> C ref b; // mutable reference to mutable class
>>>
>>> And now you can apply tail-const to it:
>>> const(C)ref c; // mutable reference to const class
>>> const(C ref) d; // const reference to const class
>>> const(C) e; // const reference to const class
>>
>> The real issue is not syntax but getting it into the compiler.
>> Apparently, there
>> are difficulties in implementing tail const in the compiler which made
>> Walter give
>> up on it in the past. It should be doable, but Walter is totally sick of the
>> issue and doesn't want to put the time in to do it - he has plenty on his plate
>> as it is. So, if it's going to be done, someone else has to step up to
>> the plate
>> and do it. And with the general lack of dmd developers, that hasn't
>> happened. No
>> one thus far has had both the inclination and the time.
>
> Well... I just took a quick look at the problem from inside the
> compiler. The issue is this: the compiler has a type hierarchy, and
> TypeClass is one type in it. There is no separate type for a class
> reference, it just uses TypeClass do designate a class reference, which
> means that if your TypeClass has the const or immutable modifier, so
> does your reference. So either we create a TypeClassRef to designate
> the reference, or we add additional flags to TypeClass for the
> reference's modifier; in either case many parts of the semantic
> analysis has to be revised to take this into account.
Turns out it's there's a trick that makes it much simpler than I
expected. Patch coming soon. ;-)
--
Michel Fortin
michel.fortin at michelf.com
http://michelf.com/
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