Andrei Alexandrescu <SeeWebsiteForEmail at erdani.org> wrote > max of n elements is O(n). T max( T )( T[] values ) { T result = values[0]; foreach ( i, e; values[1..$] ) { if ( max( values[i+1..$] ) > result ) { result = max( values[i+1..$] ); } } return result; } -- Simen