Should scope(exit) be valid outside of a scope?

[Don]

Consider the following code
----------
import std.stdio;

void foo(bool x)
{
    if (x)
       scope(exit) writeln("exiting");
    writeln("body");
}
----------
If the scope(exit) isn't in a compound statement (ie, if it isn't inside 
{}), the 'scope' applies only to the statement itself, so that's 
identical to:
    if (x) writeln("exiting");
which is useless and probably not what was intended.
Ditto for scope(success).

Currently the scope(exit) doesn't get executed at all (it's bugzilla 
1894). But I suspect that any such use of scope guards is a bug.
Can we just make it illegal?