toStringz or not toStringz
Regan Heath
regan at netmail.co.nz
Tue Jul 12 07:50:07 PDT 2011
On Tue, 12 Jul 2011 15:18:04 +0100, Steven Schveighoffer
<schveiguy at yahoo.com> wrote:
> On Tue, 12 Jul 2011 09:54:15 -0400, Regan Heath <regan at netmail.co.nz>
> wrote:
>
>> On Fri, 08 Jul 2011 18:59:47 +0100, Walter Bright
>> <newshound2 at digitalmars.com> wrote:
>>
>>> On 7/8/2011 4:53 AM, Regan Heath wrote:
>>>> On Fri, 08 Jul 2011 10:49:08 +0100, Walter Bright
>>>> <newshound2 at digitalmars.com>
>>>> wrote:
>>>>
>>>>> On 7/8/2011 2:26 AM, Regan Heath wrote:
>>>>>> Why can't we have the
>>>>>> compiler call it automatically whenever we pass a string, or char[]
>>>>>> to an extern
>>>>>> "C" function, where the parameter is defined as char*?
>>>>>
>>>>> Because char* in C does not necessarily mean "zero terminated
>>>>> string".
>>>>
>>>> Sure, but in many (most?) cases it does. And in those cases where it
>>>> doesn't you
>>>> could argue ubyte* or byte* should have been used in the D extern "C"
>>>> declaration instead. Plus, in those cases, worst case scenario, D
>>>> passes an
>>>> extra \0 byte to those functions which either ignore it because they
>>>> were also
>>>> passed a length, or expect a fixed sized structure, or .. I don't
>>>> know what as I
>>>> can't imagine another case where char* would be used without it being
>>>> a "zero
>>>> terminated string", or passing/knowing the length ahead of time.
>>>
>>> In the worst case, you're adding an extra memory allocation and
>>> function call overhead (that is hidden to the user, and not
>>> turn-off-able). This is not acceptable when interfacing to C.
>>
>> This worst case only happens when:
>> 1. The extern "C" function takes a char* and is NOT expecting a "zero
>> terminated string".
>> 2. The char[], string, etc being passed is a fixed length array, or a
>> slice which has no available space left for the \0.
>>
>> So, it's rare. I would guess a less than 1% of cases for general
>> programming.
>
> What if you expect the function is expecting to write to the buffer, and
> the compiler just made a copy of it? Won't that be pretty surprising?
Assuming a C function in this form:
void write_to_buffer(char *buffer, int length);
You might initially extern it as:
extern "C" void write_to_buffer(char *buffer, int length);
And, you could call it one of 2 ways (legitimately):
char[] foo = new char[100];
write_to_buffer(foo, foo.length);
or:
char[100] foo;
write_to_buffer(foo, foo.length);
and in both cases, toStringz would do nothing as foo is zero terminated
already (in both cases), or am I wrong about that?
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