reddit discussion on article by bearophile

[bearophile]

Timon Gehr:

> Hmm. How would that work? A and B don't have an own type.
> Your program is equivalent to
> 
> import std.stdio;
> enum A = 0;
> enum B = 1;
> void main() {
>      writeln(B); // prints 1 because B is replaced with 1.
> }

Right, my mental model of nameless enums was very wrong. I was thinking of them more like symbols (all nameless enums aren't grouped under a common name).


> You could use mixins to automatically generate
> alias E.A A;
> alias E.B B;
> // ...
> 
> for a given enumerated type.

Right, but I don't know if I will ever need this.

Bye and sorry,
bearophile