Request for pre-review: std.serialization/orange

[Robert Jacques]

On Tue, 04 Oct 2011 12:54:27 -0400, Jacob Carlborg <doob at me.com> wrote:

> On 2011-10-04 17:14, Robert Jacques wrote:
>> I'm sorry, you're right. In my mind b extended to the end of the a
>> array, for some reason. However, if you do define b to extend to the end
>> of the a array, then it can append without allocating:
>>
>> auto a = [0, 1, 2, 3, 4];
>> auto b = a[2 .. $];
>> b ~= 5;
>> assert(b[0]==2);
>> a[2] = 10;
>> assert(b[0]==10);
>>
>> So please don't dismiss this point.
>>
>
> Hmm, D1 and D2 behaves differently in this case. In D1 "a" is not
> changed when "b" is changed. Since you append to "b" I though that it
> would always require a reallocation of "b".

Appending has never mandated reallocation. Maybe you're confusing it with concatenation (i.e. b = b ~ 5;), which does always reallocate. Or the period in time when the anti-array-stomping parts of druntime was overly conservative and would have prevented b from appending in place.