Anonymous function syntax

[Rory McGuire]

Perhaps bearofile refers to this:

import std.stdio;

string getit(alias runme)() {
        return runme("b","da");
}

string getit2(string delegate(string,string) dg) {
        return dg("b", "da");
}

void main() {
        writefln("this is a %s", getit!((a,b){ return "lam"~a~b; })());
        /+writefln("this is a %s too", getit2((a,b){ return "lam"~a~b; }));
        /*lambdas.d(13): Error: undefined identifier a
        lambdas.d(13): Error: undefined identifier b
        lambdas.d(13): Error: function lambdas.getit2 (string
delegate(string, string) dg) is not callable using argument types (_error_
delegate(_error_, _error_))
        lambdas.d(13): Error: cannot implicitly convert expression
(__dgliteral4) of type _error_ delegate(_error_, _error_) to string
delegate(string, string)
        */
        +/
        writefln("this is a %s too", getit2((string a, string b) { return
"lam"~a~b; }));
}


Cheers,
Rory


On Thu, Sep 22, 2011 at 12:50 AM, Andrei Alexandrescu <
SeeWebsiteForEmail at erdani.org> wrote:

> On 9/21/11 5:29 PM, bearophile wrote:
>
>> Walter Bright:
>>
>>  D
>>>      (a,b) { return a + b; }
>>>
>>
>> In D to define a true lambda you need types too:
>> auto f = (int a,int b){ return a + b; };
>>
>
> No.
>
> Andrei
>
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