A modest proposal: eliminate template code bloat
Artur Skawina
art.08.09 at gmail.com
Sun Apr 8 08:59:53 PDT 2012
On 04/08/12 17:20, Dmitry Olshansky wrote:
> On 08.04.2012 18:21, Artur Skawina wrote:
>> On 04/08/12 13:01, Dmitry Olshansky wrote:
>>> 3. After any function was generated compiler checks an entry in the duplicate table that matches size, followed by matching checksum and only then (if required) doing a straight memcmp. If it happens that there is a match compiler just throws generated code away and _aliases_ it's symbol to that of a matched entry.
>>> (so there has to be an alias table if there isn't one already)
>> [...]
>>> Thoughts?
>>
>> Don't forget that this needs to work:
>>
>> static auto f(T)(T a) { return a; }
>> assert(cast(void*)&f!int!=cast(void*)&f!uint);
> A reference to spec page plz.
A reference to *a* D spec, please...
There isn't one, but that does not mean that common sense does
not need to apply.
Do you really suggest making different template instantiations
identical, just because the compiler happened to emit the same
code? The situation is not very different from
const int a = 1; const uint b = 1; assert(&a!=&b);
The user can take the addresses, compare them, use as AA keys,
set breakpoints etc.
Note that my point is just that the compiler needs to emit a dummy
so that the addresses remain unique, eg
module.f!uint:
jmp module.f!int
that only is used when taking the address. Even calling f!int()
instead of the uint version could be acceptable, as long as there
is a compiler option to turn this optimization off (think breakpoints).
artur
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