What to do about default function arguments

[Walter Bright]

On 4/25/2012 10:20 PM, H. S. Teoh wrote:
> On Wed, Apr 25, 2012 at 10:08:26PM -0700, Walter Bright wrote:
>> On 4/25/2012 9:42 PM, H. S. Teoh wrote:
>>> This is bad. What if you have two delegates with different default
>>> arguments? What would this code do:
>>>
>>> 	auto foo = (int a=1) { return a; };
>>> 	auto bar = (int a=2) { return a; };
>>> 	writeln(foo());
>>> 	writeln(bar());
>>>
>>> ?
>>
>> Give you two error messages, because default arguments wouldn't be
>> allowed for delegates.
>
> No I mean the current behaviour. And I just checked: dmd compiles it
> fine, and prints 1 for both cases (which is wrong).

Hence the problem :-)