Let's not make invariants const
Jonathan M Davis
jmdavisProg at gmx.com
Sat Aug 4 00:15:35 PDT 2012
On Saturday, August 04, 2012 09:06:19 Era Scarecrow wrote:
> As mentioned before, doesn't 'const' _only_ apply to the current
> (this) object and not anything else? Besides the contracts can't
> have lasting side effects that would change logical execution.
> How would changing the current object in an invariant be correct
> in release code?
The problem is that if the this pointer/reference is const, then you can't
call any member functions which aren't const, and you can't call any non-const
functions on any member variables, because _they're_ const, because the this
pointer/reference is const. And there are plenty of types out there which
_can't_ have many of their member functions be const and do what they need to
do, because D's const is both physical and transitive (unlike C++'s const).
So, it's quite easy to get into a situation, where you can't call much of any
functions at all if the this pointer/reference is const even though calling
the non-const functions wouldn't actually mutate anything.
- Jonathan M Davis
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