Function pointers/delegates default args were stealth removed?

[Walter Bright]

On 8/26/2012 6:55 PM, Timon Gehr wrote:
> On 08/27/2012 02:44 AM, Walter Bright wrote:
>> On 8/26/2012 4:50 PM, Timon Gehr wrote:
>>> On 08/27/2012 12:41 AM, Walter Bright wrote:
>>>>
>>>> The trouble for function pointers, is that any default args would need
>>>> to be part of the type, not the declaration.
>>>>
>>>
>>> They could be made part of the variable declaration.
>>
>> You mean part of the function pointer variable?
>>
>
> Yes.
>
>> Consider what you do with a function pointer - you pass it to someone
>> else. That someone else gets it as a type, not a declaration.
>
> If it is a template function, yes. But then you may as well pass the
> function pointer variable per alias, which is common.

You pass the function declaration by alias, not the function pointer 
declaration. In which case you will get the default arguments.

>
> Otherwise someone else gets nothing but a parameter declaration.
>
>> I.e. you lose the default argument information, since that is not attached to the
>> type.
>>
>
> I think most valid existing use cases would still be supported:
>
> int execFunctionPointer(int function(int = 2) fun){
>      return fun();
> }
>
> auto dg = (int x, int y=2){ return x+y; }
> writeln(range.map!dg());
>
> int function(int=3)[] funs;
> funs[0]();
>
> It is up to you if it is worth the effort, of course.

and it falls apart immediately once you try to transfer that function pointer 
anywhere.