Setting defaults to variadic template args

[luka8088]

And the simplest solution wins:

module program;

import std.stdio;
import std.traits;
import std.typetuple;

struct Event (T1 = int, T2 = float, Telse...) {

   alias TypeTuple!(T1, T2, Telse) T;

   void F (T args) {
     writeln(typeid(typeof(args)));
   }

}

void main () {

   Event!() e1;

   e1.F(5, 6);

}

I hope that you found the solution that you where looking for.

On Tuesday, 2 October 2012 at 13:49:56 UTC, luka8088 wrote:
> Or maybe... This seems like a much better solution:
>
>
> module program;
>
> import std.stdio;
> import std.traits;
> import std.typetuple;
>
> template SelectTrue (bool condition, T) {
>   static if (condition)
>     alias T SelectTrue;
> }
>
> struct Event (T...) {
>
>   alias TypeTuple!(T,
>     SelectTrue!(T.length < 1, int),
>     SelectTrue!(T.length < 2, float),
>   ) T2;
>
>   void F (T2 args) {
>     writeln(typeid(typeof(args)));
>   }
>
> }
>
> void main () {
>
>   Event!() e1;
>
>   e1.F(5, 6);
>
> }
>
>
>
> On Tuesday, 2 October 2012 at 13:44:10 UTC, luka8088 wrote:
>>
>> module program;
>>
>> import std.stdio;
>> import std.traits;
>> import std.typetuple;
>>
>> struct Event (T...) {
>>
>>  alias EraseAll!(void, TypeTuple!(T,
>>    Select!(T.length < 1, int, void),
>>    Select!(T.length < 2, float, void),
>>  )) T2;
>>
>>  void F (T2 args) {
>>    writeln(typeid(typeof(args)));
>>  }
>>
>> }
>>
>> void main () {
>>
>>  Event!() e1;
>>
>>  e1.F(5, 6);
>>
>> }
>>
>>
>> On Tuesday, 2 October 2012 at 13:15:08 UTC, Manu wrote:
>>> Is it possible?
>>>
>>> Eg:
>>> struct Event(T... = (int, float))
>>> {
>>>   void F(T...); // <- should default to F(int, float)
>>> }
>>>
>>> Does anyone have any clever tricks that will work in this 
>>> scenario? Some
>>> magic tuple syntax?