Eliminate redundancy of dup/idup
kenji hara
k.hara.pg at gmail.com
Sun Sep 9 09:26:07 PDT 2012
Yes, This works just as expected.
import std.stdio;
void main()
{
char[] a = dup("Hello");
string b = dup(a);
writeln(a); // prints "Hello"
writeln(b); // prints "Hello"
assert(cast(void*)a.ptr !is cast(void*)b.ptr); // elements are duplicated
}
Kenji Hara
2012/9/10 Jesse Phillips <jessekphillips+D at gmail.com>:
> On Sunday, 9 September 2012 at 15:32:01 UTC, kenji hara wrote:
>>
>> Finally, built-in dup and idup are merged into library dup(). Destroy!
>>
>> Kenji Hara
>
>
> Well, that is pretty awesome. I didn't see an example which says this would
> work, but I expect it would?
>
> char[] a = dup("Hello");
> string b = dup(a);
>
> I'm not as familiar with the pure to immutable but I believe to
> immutable(char)[] is or should be valid right?
More information about the Digitalmars-d
mailing list