template mixin function name mangling

[John Colvin]

On Monday, 22 April 2013 at 09:03:24 UTC, Peter Alexander wrote:
> mixin template A() {
>     extern(C) int foo() { return 1; }
> }
>
> mixin template B() {
>     extern(C) int foo() { return 2; }
> }
>
> mixin A a;
> mixin B b;
>
> void main() {
>     int x = a.foo() + b.foo();
> }
>
> If both foo's have the same symbol, then how am I able to 
> disambiguate them in code?
>
> Maybe duplicate extern(C) template mixin symbols need to be an 
> error?

If there are true duplicates then it would need to be an error. 
However, if a mixin uses a mixin identifier then it's going to 
need to be mangled anyway, so only

mixin A;
mixin B;

would have to be an error. It already is an error, but 
unfortunately only when you reference the content of the mixin, 
not at the mixin statement.