Enumeration Type-Safety in D
Jonathan M Davis
jmdavisProg at gmx.com
Thu Nov 7 08:04:07 PST 2013
On Thursday, November 07, 2013 14:25:38 Nordlöw wrote:
> What is the state and plans on type-safety of enums in D?
>
> I expected
>
> import std.stdio: writeln;
>
> void main(string args[]) {
> enum E {x, y, z}
> E e;
> writeln(e);
> e = cast(E)3;
> writeln(e);
> }
>
> to fail to compile because of D's otherwise strong static
> type/range checking or at least give an RangeException when run.
>
> To my surprise, it instead prints
>
> cast(E)3
>
> Is this really the preferred default behaviour for the majority
> of use cases?
If you're casting, then I think that it's perfectly reasonable that this sort
of thing can happen. The problem is when it happens without casting. e.g.
enum E : string { a = "hello", b = "goodbye" }
void main()
{
E foo = E.a;
foo ~= " world";
assert(foo == "hello world");
}
or
enum E : int { a = 1, b = 2 }
void main()
{
E foo = E.a | E.b;
assert(foo == 3);
}
IMHO, it should not be legal to construct invalid enums without casting, but
unfortunately, right now, it very much is. For the most part, you can do
operations on enums that are completely valid for their base type, and the
result ends up being the enum type instead of the base type like it should. I
don't know what the odds are of getting this fixed, but I think that it should
be.
However, even it were properly enforced that operations done on enum values
would either be guaranteed to result in a valid enum value or would result in
the base type instead of the enum type, I'd still expect casting to get around
that as casting is a blunt instrument which forces the issue. As others have
pointed out, you should use std.conv.to if you want the conversion to be
checked for validity.
- Jonathan M Davis
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