The "no gc" crowd

[Dicebot]

On Friday, 11 October 2013 at 18:22:46 UTC, Sean Kelly wrote:
> It should.  Stripping "shared" just means that you'll be able 
> to call any function available on the struct as opposed to only 
> explicitly shared functions.  And the mutex gives you atomic 
> behavior (assuming you use the mutex properly anywhere else you 
> access the struct).

How would it know which entity is associated with that mutex? (== 
which to strip shared from)