function overloading of address

[ketmar via Digitalmars-d]

On Tue, 2 Dec 2014 18:40:45 -0800
"H. S. Teoh via Digitalmars-d" <digitalmars-d at puremagic.com> wrote:

> On Wed, Dec 03, 2014 at 04:31:11AM +0200, ketmar via Digitalmars-d wrote:
> > On Tue, 2 Dec 2014 18:18:26 -0800
> > "H. S. Teoh via Digitalmars-d" <digitalmars-d at puremagic.com> wrote:
> [...]
> > > How do you take the address of specific overload, though?
> >
> > declare the necessary function type instead of auto:
> > 
> >   void function (int) pfoo = &foo;
> 
> Ah, of course. I'm getting too used to type inference. :-P
me too. the first thing i tried was `&foo(0)` to hint the type.
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