Bug in compiler?
ketmar via Digitalmars-d
digitalmars-d at puremagic.com
Mon Dec 15 06:33:34 PST 2014
On Mon, 15 Dec 2014 16:01:35 +0200
Shachar Shemesh via Digitalmars-d <digitalmars-d at puremagic.com> wrote:
> Please consider the following program:
> import std.exception;
>
> void main()
> {
> struct A {
> int a;
>
> @disable this(this);
> @disable ref A opAssign(const ref A);
>
> ref A opOpAssign(string op: "~")(int data) {
> a += data;
>
> return this;
> }
> }
>
> auto a = A(2);
>
> a ~= 3;
>
> assertThrown!Exception(a ~= 3);
> }
>
> Compilation (dmd 2.066.1) fails on the assertThrown line:
> Error: struct test.main.A is not copyable because it is annotated with
> @disable
>
> What I do not understand is why A should need to be copyable. Where is
> the copy made? I'm guessing this is because of the lazy definition of
> the expression, but still I don't see any reason to create a copy.
yes, this is due to `lazy` in assrtThrown. what `lazy` does is actually
creating a lambda. then compiler tries to deduce the type of the
expression and it got `A`. so it generates the code like
`A expression`. it can't see `ref` there, as `a` type is `A`, not
`ref A`.
you can workaround that with creating the necessary lambda manually:
assertThrown!Exception((ref A aa) { aa ~= 3; }(a));
tl;dr: no, it's not a bug in the compiler. but the error message is
misleading and you are required to understang some internals to make
sense out of it.
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