Smart pointers instead of GC?
Frank Bauer
y at z.com
Sat Feb 1 22:00:20 PST 2014
On Sunday, 2 February 2014 at 05:41:53 UTC, Andrei Alexandrescu
wrote:
> Sure. While you're young typecheck this:
>
> class A {
> auto stuff() { ...; return this; }
> }
>
>
> Andrei
It would be a Borrowed!A, I would say, no matter how an A is
allocated. A GC!A, an ARC!A and an Owning!A convert equally well
to a Borrowed!A. As long as the Borrowed!A is in use (i.e. scope)
after stuff() returns, the A object must not be freed (compiler
enforced). Would that make sense?
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