Why is int implicitly convertible to ulong?
Hannes Steffenhagen
cubicentertain at gmail.com
Fri Feb 21 04:41:07 PST 2014
The specific problem here was when working with std.json.
std.json distinguishes between UINTEGER and INTEGER, so I had
code like
static if(is(T : ulong)) {
// must be UINTEGER
} else static if(is(T : long)) {
// can be either INTEGER or UINTEGER
}
I've since found out about isSigned and isUnsigned, still it was
mighty confusing for me that the first case was selected for
signed types.
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