Should aliasing a lambda expression be allowed?

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On Thursday, 16 November 2017 at 13:05:51 UTC, Petar Kirov 
[ZombineDev] wrote:
> On Wednesday, 15 November 2017 at 19:29:29 UTC, Steven 
> Schveighoffer wrote:
>> On 11/15/17 11:59 AM, Andrea Fontana wrote:
>>> On Wednesday, 15 November 2017 at 15:25:06 UTC, Steven 
>>> Schveighoffer wrote:
>>>> alias foo = lambda1;
>>>> alias foo = lambda2;
>>> 
>>> What?
>>
>> Yep. Would never have tried that in a million years before 
>> seeing this thread :) But it does work. Tested with dmd 
>> 2.076.1 and 2.066. So it's been there a while.
>>
>> -Steve
>
> I guess you guys haven't been keeping up with language changes 
> :P
>
> https://dlang.org/changelog/2.070.0.html#alias-funclit
>
> And yes, you can use 'alias' to capture overload sets.
> See also:
>
> https://github.com/dlang/dmd/pull/1660/files
> https://github.com/dlang/dmd/pull/2125/files#diff-51d0a1ca6214e6a916212fcbf93d7e40
> https://github.com/dlang/dmd/pull/2417/files
> https://github.com/dlang/dmd/pull/4826/files
> https://github.com/dlang/dmd/pull/5162/files
> https://github.com/dlang/dmd/pull/5202
>
> https://github.com/dlang/phobos/pull/5818/files

Yes, as far as I understand this is just the normal way that you 
add a symbol to an existing overload set, except now it also 
interacts with the functionality of using an alias to create a 
named function literal. Kind of interesting because I don't think 
it was possible to do this before, e.g.:

int function(int) f1 = (int n) => n;
int function(int) f2 = (char c) => c;

Would obviously be rejected by the compiler. However, using the 
alias syntax we can  create an overload set from function 
literals in addition to regular functions.