So why double to float conversion is implicit ?

[codephantom]

On Monday, 23 October 2017 at 21:51:24 UTC, Basile B. wrote:
> ---
> /**
>  * Wraps a floating point type that doesn't follow D permissive 
> float conversion
>  * rules.
>  *
>  * In D, as in C++, implicit conversion from $(D double) to $(D 
> float) is allowed,
>  * leading to a possible precision loss. This can't happen when 
> using this wrapper.
>  */

Want to hammer in a nail.. just go ahead and use a bulldozer ;-)

Simple things should be simple.

I cannot see how the simplest solution would be any other than to 
have a compiler option for warning you of implicit conversions.