hacky way to get explicit default constructor on struct :P
LunaticWare
exemple at gmail.com
Sat Oct 28 16:59:03 UTC 2017
Event if there is no default constructor on struct we can still
make one that work as well as if it were implemented, here is my
example n__n
------
import std.format;
import std.stdio;
struct Player
{
string name = "Baz";
float[2] position = [0, 0];
// Adding an explicit constructor to struct =)
// But we can't enforce it since this relies on it =(
static ref auto opCall(string name = "Bar", float x = 1,
float y = 1)
{
// Even if we give no argument opCall will still be
called ;)
writefln("Entering the explicit constructor as '%s'",
name);
// Taking advantage of the implicit constructor
Player self;
// Initializing all the members
self.name = name;
self.position[0] = x;
self.position[1] = y;
// Returning the reference of the object
return self;
}
string toString()
{
return format("Hello i am '%s' and at the coordinate x%s
/ y%s",
this.name, this.position[0], this.position[1]);
}
}
void main()
{
auto foo = Player("Foo", 2.7, 10.6);
auto bar = Player();
Player baz;
writefln("%s\n%s\n%s", foo, bar, baz);
}
// == RDMD OUTPUT ==
// Entering the explicit constructor as 'Foo'
// Entering the explicit constructor as 'Bar'
// Hello i am 'Foo' and at the coordinate x2.7 / y10.6
// Hello i am 'Bar' and at the coordinate x1 / y1
// Hello i am 'Baz' and at the coordinate x0 / y0
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