pow

[H. S. Teoh]

On Wed, Mar 21, 2018 at 03:56:00PM +0000, aerto via Digitalmars-d wrote:
> why pow(256, 27) gives 0, instead of
> 105312291668557186697918027683670432318895095400549111254310977536L

Because 256, being an int type, can only hold a 32-bit result, the
maximum of which is 2^31 (or 2^32 if you use uint). But 256^27 = 2^216,
far bigger than a 32-bit int can hold.

As Adam said, you probably want to use BigInt instead:

	import std.bigint;
	auto result = pow(BigInt(256), 27);


T

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