`acos` returning `-nan`?
Jonathan Levi
catanscout at gmail.com
Sat Nov 23 17:31:22 UTC 2019
I have a `double` (from a math equation) which when logged is
`-1` but when a `acos` it it returns `-nan`?
The `double` has different bit representation than a normal `-1`
but I do not see how that is messing up its `acos`.
The `double`'s representation is: true,1023,58720256.
This will reproduce the problem:
```
import std;
void dWrite(double d) {
import std.stdio;
import std.conv;
import std.bitmanip;
auto dr = DoubleRep(d);
writeln(d,"\t",dr.sign,"\t", dr.exponent,"\t", dr.fraction);
}
double fromRep(bool sign, ushort exponent, ulong fraction) {
DoubleRep r;
r.sign = sign;
r.exponent = exponent;
r.fraction = fraction;
return r.value;
}
void main() {
double failing = fromRep(true,1023,58720256);
double lookalike = -1;
failing.dWrite;
lookalike.dWrite;
failing.acos.dWrite;
lookalike.acos.dWrite;
}
```
Any idea why that is and how I could solve it?
BTW this is the how that number is created:
`cos(a.angle)*cos(b.angle) -
dot(a.axis*sin(a.angle),(b.axis*sin(b.angle)))`
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