How to prevent DMD from changing the executable files at each compilation ?

[Ecstatic Coder]

On Sunday, 29 September 2019 at 12:30:46 UTC, H. S. Teoh wrote:
> On Sun, Sep 29, 2019 at 11:15:43AM +0000, Ecstatic Coder via 
> Digitalmars-d wrote:
>> Every time I compile the same code with DMD, I get a slightly 
>> different ".exe" file on Windows.
>> 
>> fc /b basil.exe basil_old_1.exe
>> 00000118: 9F 55
>> 00000119: 8C 89
>> 00156554: 9F 55
>> 00156555: 8C 89
>> 
>> fc /b basil.exe basil_old_2.exe
>> 00000118: 9F 1B
>> 00000119: 8C 8A
>> 00156554: 9F 1B
>> 00156555: 8C 8A
>> 
>> This problem is D specific, as for instance Go will generate 
>> the same executable each time.
>> 
>> So before I implement a tool for this, is there an easy way to 
>> prevent DMD from "timestamping" its generated binaries, so 
>> that they become more "git-friendly" ?
>
> Seems this is Windows-specific; I can't reproduce this on my 
> Linux box. Which leads me to think this isn't a dmd problem; it 
> may be the linker that's inserting the timestamp. Which linker 
> is being used? Perhaps an approprate option passed to the 
> linker is what you need. You can pass options to the linker 
> with -L... (on Windows it might be /L..., not 100% sure).
>
>
> T

Ah, then I guess it's probably because I'm using the MinGW option 
when installing the DMD compiler, as unfortunately it's the only 
"lean" option that remains :(

OK, I'll try deinstalling DMD, and then reinstalling it with the 
"huge" option (=VS)...

Thanks for the hint :)