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On Monday, 11 January 2021 at 16:53:42 UTC, Ali Çehreli wrote:
> On 1/11/21 2:52 AM, ddcovery wrote:
>
> > Is it possible to us in/out in a lambda expression?
>
> I don't think so. I guess, if it has contracts, it deserves to 
> be a proper function. :)
>
> Ali

It seems that it does work, but you need to include the 
`function()` preamble; it doesn't seem to like including 
contracts with the short-form function literals.

void test(void function() f)
{
     f();
}

void main()
{
     test(function() in(1 == 0) out(; 1 == 0) {}); //Okay
}