Template type inference problem

[Salih Dincer]

On Wednesday, 2 October 2024 at 08:55:15 UTC, Manu wrote:
> Does anyone understand why this doesn't work?
> ```d
> void f(T)(const(T)[] x, const(T)* y) {}
> void test()
> {
>     int*[] x;
>     const int* y;
>     f(x, &y);
> } /* Error:
> template `f` is not callable using argument types `!()(int*[],
> const(int*)*)`
>         Candidate is: `f(T)(const(T)[] x, const(T)* y)` */
> ```
> Should this work? It looks like it should work to me.

Hi Manu, what did you do, any progress? So why don't you use 2 
aliases like T, R? For example:

```d
template func(T : const T, R : const R)
{
   void func(const(T)[] x, const(R)* y)/*
   void func(T[] x, R* y)//*/
   {
     typeid(x).writeln(": ", T.stringof);
     typeid(y).writeln(": ", R.stringof);
   }
}

import std.stdio;
void main()
{
   const
       int[] x;
   //const
       int y;
     
   func(x, &y); /* Output:
        const(int)[]: int
        const(int)*: int  */

   const
       int* [] a;
   //const
       int* b;
   
   func(a, &b); /* Output
        const(const(int)*)[]: const(int)*
        const(const(int)*)*: int*  */
}
```

SDB79