[phobos] advance() for infinite random access ranges?

[Denis]

On Sun, Aug 15, 2010 at 4:29 AM, David Simcha <dsimcha at gmail.com> wrote:
> I've thought some more about how to support slicing in the case of
> take(someInfiniteRange, someNumber) and I think it would be a good idea to
> require infinite random-access ranges to support an advance() function.
>  This would basically be like slicing, but only change the beginning of the
> range, not the end (since there is no end of an infinite range).  Calling
> infiniteRange.advance(N) would be equivalent to calling
> infiniteRange.popFront() N times, except that advance() would have O(1) time
> complexity.  Sound good?  Any alternative suggestions?
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O(1) advance() is not always possible (not that it means your
suggestion is bad).